1. Concurrent Forces 2. Strain 3. Modulus of elasticity. 4. 0.053″ 5. internal forces act in the opposite direction from that assumed. 6. I and II 7. 200 psi 8. unit stress at which the material continues to deform with not increase in load. 9. up to the elastic limit, unit stress is in direct Read more
Statics
Find required diameter if elongation not to exceed 0.005″ and find required diameter if unit stress not exceed 24,000 psi Read more
ksi of steel = 20,000,000 psi modulus of elasticitY = hooke’s law or young’s modulus (same thing) Read more
Unit stress (f) is equal to the load (P) divided by the cross sectional area (A) Read more