Temperature decrease of 50 degrees
read moreFind required diameter if elongation not to exceed 0.005″ and find required diameter if unit stress not exceed 24,000 psi.
read moreksi of steel = 20,000,000 psi modulus of elasticitY = hooke’s law or young’s modulus (same thing)
read moreUnit stress (f) is equal to the load (P) divided by the cross sectional area (A).
read moreDivide into rectangles and calculate the area of each rectangle.
read moreUse free body diagram to solve for internal forces and moment about a point on a simply supported beam.
read more